Wednesday, July 8, 2009 – Factoring Part Four – The Combo #2 and The Hard Trinomial

Up to now, we have learned how to factor the “simple” trinomial, those that are in the form of ax^2 + bx +c, where either a = 1 (x^2 + bx + c), or those where you have a difference of squares, or a difference of squares left after you take out a common factor (combo #1). Today we start to look at the “hard” trinomial, those in the form of  ax^2 + bx +c, where a ≠ 1 where either “a” is a common factor of “b” and “c” (Combo #2), or “a” is not a common factor of BOTH “b” and “c”, the “hard” trinomial.  There are two videos to watch below.